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Mathematics 17 Online
OpenStudy (anonymous):

How do you find the foci of an ellipse.

OpenStudy (anonymous):

(plus/minus a*e,0) where e is the eccentricity (sqrt(1-b^2/a^2)) for an ellipse in standard position.

OpenStudy (anonymous):

a(times)e?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Can I have an example??

OpenStudy (anonymous):

Make up your own...:-)

OpenStudy (anonymous):

... Please?

OpenStudy (anonymous):

You bring me the ellipse, I will show you how to plug the numbers in....

OpenStudy (anonymous):

Okay, vertical ellipse center at origin, spaces to the sides 6, spaces vertically - 10

OpenStudy (anonymous):

=10*

OpenStudy (anonymous):

Work with that.

OpenStudy (anonymous):

No, you are supposed to do the work, not me..... Bring me an equation (and in standard form)

OpenStudy (anonymous):

Fine.

OpenStudy (anonymous):

Give me a sec.

OpenStudy (anonymous):

(x^2/36)+(y^2/100)=1

OpenStudy (anonymous):

I think that that is standard.

OpenStudy (anonymous):

That is not in standard position....

OpenStudy (anonymous):

I'm not too good at this.

OpenStudy (anonymous):

What is?

OpenStudy (anonymous):

(x^2/100)+(y^2/36)=1 Let's do this one, do you know what a and b are?

OpenStudy (anonymous):

Yes. a=10 and b=6

OpenStudy (anonymous):

eccentricity (sqrt(1- b^2/a^2)) ?

OpenStudy (anonymous):

(sqrt(1-36)/100)

OpenStudy (anonymous):

sqrt(35)/100

OpenStudy (anonymous):

Right?

OpenStudy (anonymous):

(sqrt(1- b^2/a^2)) One minus .........

OpenStudy (anonymous):

-35*

OpenStudy (anonymous):

isqrt(35)/100

OpenStudy (anonymous):

i*sqrt(35)/100

OpenStudy (anonymous):

1 - (36/100) = 64/100 and sqrt is 0.8

OpenStudy (anonymous):

How does it equal 64/100?

OpenStudy (anonymous):

1 = 100/100 and if you take away 36/100 you get 64/100

OpenStudy (anonymous):

Oh!

OpenStudy (anonymous):

Okay, I read the perentheses wrong.

OpenStudy (anonymous):

So now we have e = 0.8 (it's always between 0 and 1)

OpenStudy (anonymous):

Yep.

OpenStudy (anonymous):

foci (plus/minus a*e,0)?

OpenStudy (anonymous):

+/-(10*.8,0)

OpenStudy (anonymous):

Done.

OpenStudy (anonymous):

So then we have +/-8,0

OpenStudy (anonymous):

Right?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

So those are the foci?!

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

Yes!

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

2 MEdals then I guess. lol

OpenStudy (anonymous):

ur welcome....(careful when a is less than b, that's an ellipse stood on end)

OpenStudy (anonymous):

I know.

OpenStudy (anonymous):

Wait.

OpenStudy (anonymous):

Does a change in the essentricity?

OpenStudy (anonymous):

Does "a" change to b?

OpenStudy (anonymous):

If b is grater?

OpenStudy (anonymous):

That's an exercise for the reader.....:-)

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

:-)

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