find the gcf plz explian a^3b times a^2 times b^2
gcf is greatest common factor, right?
yes
so, the largest common "a" term in both is the a^2, since the first has an "a^3" and the second only has "a^2" in it. In the same way, the largest b common to both is just b... even though the second term has a "b^2", the first term only has "b". So the GCF is (a^2)b
is there an easyer way to explian it?
:) I could try... did I lose you?
oh, I may have misunderstood the question...
kind of
Is the problem really all one term? I first read it as two separate terms... misread the middle "times" as the word "and" a^3b times a^2 times b^2
yes that is the question
Like this? \[a ^{3}b * a ^{2}b ^{2}\]
Sorry, no wonder my answer was confusing.
actually instead of a multpication sign its a ( , )
Ok, that actually makes more sense. So it's two terms... \[a ^{3}b, a ^{2}b ^{2}\]
yes
So, GCF is like factoring out the biggest amount you can from both terms. To make it seem easier, just pretend b=2, so b^2 =4 Then the two terms are \[a ^{3}(2), a ^{2}(4)\]
So the GCF of this easier example would be 2a^2, since you can factor the first term as \[2a ^{2}(2a)\] and the second term as \[2a ^{2}(b ^{2})\]
See why 2a^2 is the GCF in that example?
kind of how did you get to \[2a ^{2}(b ^{2})\]
Ug, I messed it up. should have been \[2a ^{2}(2b ^{2})\]
Maybe I shouldn't have tried for an easier example... I am confusing myself now. Let me take a quick look at it again to make sure I'm not mixing the real question with my (supposedly) easier example. Sorry for all the confusion!!
i think ive got it thank you for your time
\[a ^{3}b, a ^{2}b ^{2}\] These 2 terms can be factored like: \[(a ^{2}b)(a), (a ^{2}b)(b)\]
@ashtartamo1 Just posted the actual factoring... the GCF is the first term in parenthesis in each part. Sorry again...
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