find the slope of the curve at y=1/x-1
What's the curve?
It doesn't give it, you'd have to graph it
i'm really confused..
If this is calculus, it is probably referring to the tangent curve...
In which case it would be the derivative of the function
this is most definitely calculus, but I plugged it in to the f(x+h) - f(x) all over h formula
and ended up with 1/h^2 and I'm really confused..
You haven't learned the derivative formulas yet??? It is much shorter
what derivative formulas?!
fml
ok so ther derivative of 1/x= x^-1=x^-2 = 1/x^2. The derivative is one over x squared which is the slope
how does x^-1 = x^-2? what?
That is from the formula for derivatives of x to a power. you -1 from the power which in this case makes it x^-2
I don't see how it makes it x^-2 and in the back of the book the answer says -1/(x-1)^2
Lol. If you haven't learned the derivative formulas you have to do it the hard way and use the definition.
could you please show me how to do it the definition way?
or if i show you my work will you tell me what I did incorrectly?
Ok
that is really what it says in the back of the book?!
yes! i've tripple checked, i'm assuming it's wrong
no wonder people get confused \[-\frac{1}{(x-1)^2}\] is not the slope of anything
it is a FORMULA for the slope of the line tangent to the curve you need to know \(x\) to find an actual slope
they don't ask for that though, so no idea why it's in the back of the book.. jvioejiwoeajfiewao
it is not wrong in the sense that \(-\frac{1}{(x-1)^2}\) is not the formula for the slope, and we can find that if you like
can you check my work for me? i'm using the derivative function because we havn't learned any formulas
so you are working directly from the definition, right?
\[\lim_{h\to 0}\frac{f(x+h)-f(x)}{h}\] is what i assume you are using
yes! and it ended up like this..
a word of advice before you start 1) is a only algebra, but you have to do it carefully 2) work step by step, and ignore the \(h\) in the denominator until all the algebra is done in the numerator
|dw:1348102986963:dw| but then i simplified the numerator
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