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help with negative exponent fractions?! (x+3)^(-1/3)-2(x+3)^(-1/3)=3
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would it be u=(x+3^/1/3)^2?
Negative exponent means "inverse" not "negative"
For example \[x^{-a} = \frac{1}{x^a}\]
In this case \[(x+3)^{-1/3} = \frac{1}{(x+3)^{1/3}}\]
Which becomes \[\frac{1}{\sqrt[3]{x+3}}\]
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So if you have x to the `negative` a, the negative exponent indicates the `inverse` of x to the a
And just to remember this, you can basically read \(x^{-a}\) as `the inverse of x to the a` rather than say `x to the negative a`
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