Question

Simplify:

Answer 1

\[\huge \frac { \sqrt { 6 } }{ { \sqrt { 2 } +\sqrt { 3 } } } +\frac { 3 }{ { \sqrt { 6 } +\sqrt { 3 } } } -\frac { 4\sqrt { 3 } }{ { \sqrt { 6 } +\sqrt { 2 } } } \]

Answer 2

@vbfn

Answer 3

@vbfn

Answer 4

hmmm.......

Answer 5

make same denominator

Answer 6

@satellite73 help

Answer 7

isn't that just rationalizing denum??

Answer 8

ya

Answer 9

yikes

Answer 10

yo helpis

Answer 11

\[4\sqrt{2}-3\sqrt{3}\]

Answer 12

first term is \(3\sqrt{2}-2\sqrt{3}\)

Answer 13

hmm.. cant get you

Answer 14

second term is \(\sqrt{6}-\sqrt{3}\)

Answer 15

you have to multiply by the conjugate 3 times, i don't see a snap way to do it other than than
then combine like terms

Answer 16

hmm......

Answer 17

got that next ....???

Answer 18

\[\frac{\sqrt{6}}{\sqrt{2}+\sqrt{3}}\times \frac{\sqrt{2}-\sqrt{3}}{\sqrt{2}-\sqrt{3}}\]
\[=\frac{\sqrt{6}(\sqrt{2}-\sqrt{3})}{2-3}\]
\[=\frac{2\sqrt{3}-3\sqrt{2}}{-1}\]
\[=3\sqrt{2}-2\sqrt{3}\] etc etc etc

Answer 19

that is the first term. second one and third do the same way

Answer 20

okay thanks satellite

Answer 21

second