Mathematics
6 Online
OpenStudy (anonymous):
differentiate
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[\sqrt{\frac{ (x^2+1) }{ (x^2-1)}}\]
OpenStudy (anonymous):
have u tried it yet?
OpenStudy (anonymous):
Find the derivative of it
OpenStudy (anonymous):
\[1/2(\frac{ x^2+1 }{ x^2-1 })^-1/2(\frac{ (x^2-1)(2x)-(x^2+1)(2x) }{ (x^2-1)^2 }\]
OpenStudy (anonymous):
that first one is raised to the -1/2 :P
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Thats what I got
OpenStudy (anonymous):
right :)
OpenStudy (anonymous):
cool correct
OpenStudy (anonymous):
this is where i get messed up, the denominator :(
OpenStudy (anonymous):
You can probably simplify it yet if your teacher wants it that way
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[\frac{ -2x }{ \sqrt{\frac{ x^2+1 }{ x^2-1 }}(x^2-1)^2 }\]
OpenStudy (anonymous):
do you think it is -4x on top
OpenStudy (anonymous):
i simplified it with the 1/2 from earlier
OpenStudy (anonymous):
and you should probably get rid of that compound fraction
this is really ugly
OpenStudy (anonymous):
Oh good point.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
thats where im lost, how do i clean up the denominator?
OpenStudy (anonymous):
denominator only. can you...\[\frac{ (x ^{2}+1)^{\frac{ 1 }{ 2 }}(x ^{2}-1)^{2} }{ (x ^{2}-1)^{\frac{ 1 }{ 2 }} }\]
OpenStudy (anonymous):
Now do you see that the x^2-1 can be simplified
OpenStudy (anonymous):
Nice question. Good luck in your studies