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Mathematics 6 Online
OpenStudy (anonymous):

differentiate

OpenStudy (anonymous):

\[\sqrt{\frac{ (x^2+1) }{ (x^2-1)}}\]

OpenStudy (anonymous):

have u tried it yet?

OpenStudy (anonymous):

Find the derivative of it

OpenStudy (anonymous):

\[1/2(\frac{ x^2+1 }{ x^2-1 })^-1/2(\frac{ (x^2-1)(2x)-(x^2+1)(2x) }{ (x^2-1)^2 }\]

OpenStudy (anonymous):

that first one is raised to the -1/2 :P

OpenStudy (anonymous):

Thats what I got

OpenStudy (anonymous):

right :)

OpenStudy (anonymous):

cool correct

OpenStudy (anonymous):

this is where i get messed up, the denominator :(

OpenStudy (anonymous):

You can probably simplify it yet if your teacher wants it that way

OpenStudy (anonymous):

\[\frac{ -2x }{ \sqrt{\frac{ x^2+1 }{ x^2-1 }}(x^2-1)^2 }\]

OpenStudy (anonymous):

do you think it is -4x on top

OpenStudy (anonymous):

i simplified it with the 1/2 from earlier

OpenStudy (anonymous):

and you should probably get rid of that compound fraction this is really ugly

OpenStudy (anonymous):

Oh good point.

OpenStudy (anonymous):

thats where im lost, how do i clean up the denominator?

OpenStudy (anonymous):

denominator only. can you...\[\frac{ (x ^{2}+1)^{\frac{ 1 }{ 2 }}(x ^{2}-1)^{2} }{ (x ^{2}-1)^{\frac{ 1 }{ 2 }} }\]

OpenStudy (anonymous):

Now do you see that the x^2-1 can be simplified

OpenStudy (anonymous):

Nice question. Good luck in your studies

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