Question

find a tangent line to this ellipse at the given point.

Answer 1

\[\frac{ x^2 }{ 4 }+\frac{ y^2 }{ 49 }=1\] @ \[(\sqrt{2},\frac{-7 }{ \sqrt{2} })\]

Answer 2

so explicit differentiation with respect to x?

Answer 3

f(x)-f(a) / (x-a)

Answer 4

im not sure... it just says to find a tangent line

Answer 5

anyone there>?

Answer 6

the slope of the tangent line is given by differe\[Df(x,y) = \frac{2x}{4} + \frac{2y * y'}{49} = 0\]ntiating implicitly

Answer 7

find y' from this eqn.
medal

Answer 8

i got the derivative, can you check my answer/?

Answer 9

y'=-49x/4y

Answer 10

y

Answer 11

now I plug in my point to get slope?

Answer 12

+

Answer 13

\[\frac{ -49\sqrt{2} }{ 4(\frac{ -7 }{ \sqrt{2} }) }\]

Answer 14

I am not a calculator

Answer 15

\[m=7/4\]

Answer 16

?

Answer 17

hello

Answer 18

Substitute, check true/not