Question

Please help me we the following problem
dx/dt=d/dt [t^2+4/7t]

Answer 1

=d/dt [(t^2/7t)+(4/7t)]

Answer 2

=d/dt [(t/7)+(4/7t)]

Answer 3

=d/dt [t/7] + d/dt [4/7t]

Answer 4

now i'm stuck

Answer 5

=d/dt [t/7] + d/dt [4t^(-1)/7]
=1/7 - 4/7 *(-1) t^(-1-1)

Answer 6

So, dx/dt= 1/7 +4/7t^2

Answer 7

Does it help?

Answer 8

d/dt [4t^(-1)/7]
is there a rule that explains how you got that?

Answer 9

what would happen if it were d/dt [4t/7] ?

Answer 10

Sorry I was out

Answer 11

Yes there is a rule....
d/dt [4t/7] =4/7

Answer 12

Now, This may help:
d(ax^n)/dx = a*n x^(n-1)

Answer 13

\[x'=(t^2+4/7t)'\]
\[x'=(t^2)'+(4/7t)'\]
\[x'=(2t)+(4/7t)'\]
where is the "t" in that last term, top or bottom?

Answer 14

for that matter, i may have interpreted the setup incorrectly.

\[\frac{t^2+4}{7t}~??\]
\[t^2+\frac{4}{7t}~??\]
\[t^2+\frac{4}{7}t~??\]