What is the domain of the following function? Screenshot attached!!!
Think about it this way....For any quadratic such as x^2 -2x + 1...can you think of any number where inputting an x value will lead to a false output?
Let's try x = -4 and see what happens: (-4)^2 -2(-4) + 1 = 16 + 8 + 1 = 24 + 1 = 25 25 is a real number right? So that works. Lets try x = 3 (3)^2 -2(3) + 1 = 9 - 6 + 1 = 9 + 1 - 6 = 10 - 6 = 4 Hmmm, 4 is a real number as well. How about zero... (0)^2 -2(0) + 1 = 0 - 0 + 1 = 1 Geez, I'm having trouble finding an x value that will not work. How about you?
Okay, so what is the only answer choice that makes sense in this regard? Yes! :D
The domain is the set of inputs or x values that are valid for a particular function. In this case all real x-input values or all real numbers
x = 4y - 2
Sorry about that...typos
So from there, so should be able to solve for y
And isolating y will give you the inverse of the function
You're guessing :/
Add 2 to both sides. Let me know what you get afterwards
@uzUmakhi, I'm kindly asking you not to interrupt here. Please allow her to try to solve it .
see the graph and find out the value of x where value of is infinity
Okay, but let her try to solve it first, okay @uzumakhi?
Yes, but -2 + 2 = 0 so you don't have to include that part. You will just have 2 + x = 4y after adding 2 to both sides. Now, divide both sides by 4. Let me know what you get
You know what....B IS the answer. It didn't look that way at first. Sorry
Yes, but B is the answer anyways. You had it right all along.
That's what I'm trying to tell you
But now I'm curious as to how you figured out B. You seemed to have trouble isolating y when I asked you. I'm wondering if you guessed B. You will not be able to do that for every question you get. They should have given you a harder one.
Yes, and that's unfortunate because you will need to know how to do inverse functions in the future. You will not be able to guess every time. The process of finding the inverse isn't that difficult.
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