Newton currently has an account balance of $6,225.18. He opened the account 15 years ago with a deposit of $4,543.11. If the interest compounds daily, what is the interest rate on the account?
what is the compounding formula you are given?
The formula would be 6225.18=4543.11(1+r/365)^(365*15) I think. I just don't know how to solve it.
looks good ...divide both sides by 4543.11 and exponentiate both sides with (1/(365*15))
I'm still confused. 1.37=(1+r/365)^5475 What do I do from there?
\[1.37^{1/5475}=((1+r/365)^{5475})^{1/5475}\]
you good on this?
Not really.
what part?
All of it. I can normally figure out problems like this, but when it comes to finding the rate in problems like this, I get stumped.
I understand the beginning of the problem, but when you put the most recent equation, I got even more confused.
\[(C ^{a})^{b} =C ^{ab} \]
exponentiating both sides with (1/5475) gets rid of the exponent on the right side because 5475*(1/5475) =1
So it would just be 1.37^5475=1+r/365 ?
1.37^(1/5475) =1+r/365
Ohh. Okay. So is the answer 364.02 ?
no
Omg. I got 1.00006=1+r/365 Then I multiplied 1.00006 by 365 and got 365.02 then subtracted 1 from both sides and got 364.02.
hit these keys: 5 4 7 5 \[\frac{ 1 }{ x }\] memory store 1.37 \[y ^{x}\] memory recall - 1 * 365
So 2.1% ?
yep:)
Yay. (: Finally.
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