Question

Screenshot attached. Can a function be a circle on a graph? I think it can. Am I right?

Answer 1

correct its true.

Answer 2

it is not an explicit function of x

Answer 3

a circle can only be described by an implicit function or the combination of two explicit functions

Answer 4

you can't write the equation of a circle as y = f(x), which is the form of an explicit function

Answer 5

If you were taught that a single variable "function" is one which passes the "vertical line test", then "function" means "explicit function"

Answer 6

the function you are trying to is a circle of eqn x^2 + y^2 =1 hence...

y=\[\sqrt{1-x^{2}}\]

Answer 7

yes....

Answer 8

yes its true... @charlotteakina without a fn how can be its eqn??? :)

Answer 9

sriramkumar forgot the +/- in the \sqrt(1-x^2)

Answer 10

He is wrong

Answer 11

This is the plot of sriramkumar's function

Answer 12

put x=0 dear... then you get y=sqrt(1) which either +1 or -1... @fredrickV

Answer 13

Circle: \[x^2 + y^2 = 1\]
This can be rewritten as \[y=\pm \sqrt{(1-x^2)}\]
This is two explicit functions. So the graph shown is not a plot of an explicit function.