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question about limits...
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\[\frac{ \lim }{ x->5^- }\frac{ x-2 }{ x-5 }\]
LOL!
OH.
Haha, Okay than.
so when I plug in 5 i get 3/0 which doesent seem right :(
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\[\lim_{x\rightarrow5}\frac{x-2}{x-5}=|\frac{3}0|=\infty\]
5^-
Don't understand.
\[\frac{ \lim }{ x->5^- }\]
What does it mean?
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as x approaches 5 from the left(1,2,3,4,4.9)
@Calle87 3/0 is infinity right ? now since we have x->5- which means x is very near to y but LESS than 5, so we have x-5 as negative. so the answer to this limit will be -infinity. does this make sense ?
sure does, thanks @hartnn !!
numerator is positive, denominator goes to zero through negative numbers, so the fraction will be negative therefore minus infinity
welcome :)
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thanks @satellite73 !!!
Ok. It was useful!
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