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Mathematics 19 Online
OpenStudy (anonymous):

question about limits...

OpenStudy (anonymous):

\[\frac{ \lim }{ x->5^- }\frac{ x-2 }{ x-5 }\]

OpenStudy (anonymous):

LOL!

OpenStudy (anonymous):

OH.

OpenStudy (anonymous):

Haha, Okay than.

OpenStudy (anonymous):

so when I plug in 5 i get 3/0 which doesent seem right :(

OpenStudy (klimenkov):

\[\lim_{x\rightarrow5}\frac{x-2}{x-5}=|\frac{3}0|=\infty\]

OpenStudy (anonymous):

5^-

OpenStudy (klimenkov):

Don't understand.

OpenStudy (anonymous):

\[\frac{ \lim }{ x->5^- }\]

OpenStudy (klimenkov):

What does it mean?

OpenStudy (anonymous):

as x approaches 5 from the left(1,2,3,4,4.9)

hartnn (hartnn):

@Calle87 3/0 is infinity right ? now since we have x->5- which means x is very near to y but LESS than 5, so we have x-5 as negative. so the answer to this limit will be -infinity. does this make sense ?

OpenStudy (anonymous):

sure does, thanks @hartnn !!

OpenStudy (anonymous):

numerator is positive, denominator goes to zero through negative numbers, so the fraction will be negative therefore minus infinity

hartnn (hartnn):

welcome :)

OpenStudy (anonymous):

thanks @satellite73 !!!

OpenStudy (klimenkov):

Ok. It was useful!

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