Question

The fourth corner of a parallelogram, S, is diagonally opposite P. Find S given P(1,1) Q(-3,4) R(6,10).

Answer 1

so why am I getting the prong answer when I add \[\vec{PQ}+\vec
{PR}\]

Answer 2

wrong*

Answer 3

show me how you add them

Answer 4

or I need to add this to the point P?

Answer 5

I add them to get (1,12). so I just need to add that vector to point P. how do I "show" that?

Answer 6

can I just say \[S=P+\vec{S}\]

Answer 7

does that make any since?

Answer 8

sense

Answer 9

PQ=(-3-1,4-1)=(-4,3)
PR=(6-1,10-1)=(5,9)
PQ+PR=(1,12)
now aply this vector to P to find S: (1,1)+(1,12)=(2,13)

Answer 10

ok thanks. that's exactly what I did. I was just unsure if you can just add a vector to a point. I mean I know you can (and you will get a point) but wasn't sure If I could just say that since math profs are picky about how you show things! thanks a lot

Answer 11

yw