Question

Differentiate g(u)=sqrt(2)u+sqrt(3u)

is the answer...
g'(u)=(sqrt(3)/2sqrt(u))+sqrt(2)

Answer 1

y = sqrt(x)

use the power rule:

deravite of : x^(n) is : n*x^(n - 1)

Rewrite: y = sqrt(x) as : y = x^(1/2)

y' = (1/2)(x^(.5 - 1)) = (1/2)(x^(-1/2))

y' = 1/(2*sqrt(x) )
follow same procedure u will get answet

Answer 2

\[\sqrt[2]{U}+ \sqrt {3U}\] ??

Answer 3

yes.

Answer 4

no

Answer 5

i think it is 1/2root u+1/root3u

Answer 6

am I wrong..?

Answer 7

but monore has said that

Answer 8

I got... sqrt(3)/2sqrt(u)+sqrt(2)

Answer 9

(sqrt(3)/2sqrt(u))+sqrt(2)

Answer 10

@jim_thompson5910 am I correct?

Answer 11

\[\frac{ d (u)^{5/2}}{ du }+\frac{ d(\sqrt{3u}) }{ du }\]

Answer 12

@monroe17 after differentiating the above equation you'll get the required answer

Answer 13

sqrt(3)/2sqrt(u)?

Answer 14

answer is differentiation of root xis 1/2root x as i expalined earlier through power rule and differentiation of root3x is 1/6root3u finally 1/2rootx+1/6root3u

Answer 15

I'm so confused :(