find the continuity of f(x) = {x, x<= 0 {x+1 >0 It says it's continuous from (-infinity, 0) and (0,infinity) because the lim does not exist at x=0. WHy is that?
When you approach x = 0 from the left (negative x side), you use the top expression and the values of f(x) are x. From the right, you use the lower expression. You get different answers at x = 0, so at that point, it's not continuous, but everywhere else it is.
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so if i were to reach the same number it would have been continuous throughout?
yes, but really you don't even need to "approach" in this problem... you just need to look at the value of x at x=0 and realize that the function parts don't "connect"
You'll get some problems eventually that require you to "approach" from either side because at the x=0 point, the function is undefined. You don't really need that here... It isn't continuous at x=0 because it is not connected continuously, it's that easy
okk that is clear to me
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