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OpenStudy (anonymous):
If x squared + y squared=36 and (x+2) quantity
squared=64, what is the value of xy?
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OpenStudy (anonymous):
ahhh
hartnn (hartnn):
can u find x from \((x+2)^2=64\) ??
OpenStudy (anonymous):
14
OpenStudy (anonymous):
is the answer
OpenStudy (anonymous):
for question 1.
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OpenStudy (anonymous):
cause
OpenStudy (anonymous):
x squared plus y squared=36
OpenStudy (anonymous):
2xy has to equal 28
OpenStudy (anonymous):
so half of 28, which is half of 2xy,=14
OpenStudy (anonymous):
so the answer is B.
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hartnn (hartnn):
how 2xy = 28 ?
u had x^2+y^2 ?
OpenStudy (anonymous):
Correct?
OpenStudy (anonymous):
x squared plus y squared=36
OpenStudy (anonymous):
(x+y) quantity squared=64
OpenStudy (anonymous):
it includes the number 2xy
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OpenStudy (anonymous):
which has to equal 28
OpenStudy (anonymous):
half ot 2xy=14
OpenStudy (anonymous):
xy=14
hartnn (hartnn):
is 0 in the option ?
OpenStudy (anonymous):
36+28=64
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OpenStudy (anonymous):
nope
OpenStudy (anonymous):
the answer booklet says B.
OpenStudy (anonymous):
x times y =14
OpenStudy (anonymous):
do you understand where I am getting at?
hartnn (hartnn):
hmm....maybe question is incorrect....
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OpenStudy (anonymous):
nope...
OpenStudy (anonymous):
look it
OpenStudy (anonymous):
x squared plus 2xy plus y squared=64
OpenStudy (anonymous):
x squared plus y squared=36
OpenStudy (anonymous):
36+2xy=64
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OpenStudy (anonymous):
2xy=28
OpenStudy (anonymous):
xy=14
OpenStudy (anonymous):
the value of xy=14
OpenStudy (anonymous):
therefore, the answer is B.
OpenStudy (anonymous):
do you understand where I am getting at?
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OpenStudy (anonymous):
Where are you getting 2xy? You only get 2xy if the question is:
(x + y)^2, not x^2 + y^2 (like your question says).
OpenStudy (anonymous):
look it
OpenStudy (anonymous):
the does say (x+y) quantity squared=64
OpenStudy (anonymous):
the ? does
OpenStudy (anonymous):
x squared+y squared=36
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OpenStudy (anonymous):
(x+y) quantity squared=64
OpenStudy (anonymous):
do you see now?
hartnn (hartnn):
u wrote x+2 ....
OpenStudy (anonymous):
sorry
OpenStudy (anonymous):
it meant to write (x+y) quantity squared
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OpenStudy (anonymous):
so
OpenStudy (anonymous):
as I was saying
OpenStudy (anonymous):
36+2xy=64
OpenStudy (anonymous):
2xy+28
OpenStudy (anonymous):
xy=14
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hartnn (hartnn):
then u are correct....
OpenStudy (anonymous):
xy=14
OpenStudy (anonymous):
ty
OpenStudy (anonymous):
next problem :)