Question

Need to know how to solve, (432w+2592)/(w*w+12w+36) = ((432w)/(w*w))-1 answer is w= 54,48

Answer 1

\[{(432w+2592)\over(w^2+12w+36)} ~~~~= {{{(432w)}\over {(w^2)}}~~-1} \]

Answer 2

simplify the trinomial

Answer 3

(432w+2592)/((w+6)^2)=(432-w^2)/(w^20

Answer 4

okay multiply EACH TERM by \[\frac{ \left(\begin{matrix}\\(w ^{2})(x+6)^{2} \end{matrix}\right) }{ 1}\]

Answer 5

but simplify by crossing out what yu can befor multiplying.

Answer 6

I got this but pretty sure it's wrong:
2592w^4+31104w^5+93312w^2 = -w^6 - 12w^4-36w^4

Answer 7

\[(w ^{2})(432w+2592)=(w+6)^{2}(432w)-(w ^{2})(w+6)^{2}\]
simplify

Answer 8

unless thats what yu got already

Answer 9

432w^3+2592w^2 = 432w^3+432w^2+15552w-w^4+12w^3+36w^2

Answer 10

ok the w+6 needs to be put back into the trinomial first

Answer 11

so do (w^2)(w^2+12w+36) times each term?

Answer 12

no thats already been done. im talking about this part
432w^3+432w^2+15552w-w^4+12w^3+36w^2
did yu multiply the 432w by the trinomial?

Answer 13

yes

Answer 14

okay then simplify all.

Answer 15

set it equal to zero or just simplify both sides?

Answer 16

get the w one one side. or yeah set to 0

Answer 17

-w^4-12w^3-2196w^2+15552w=0

Answer 18

can yu simplify more?

Answer 19

not that I know of

Answer 20

a 'w'maybe?

Answer 21

I'm not sure how to simplify it any further

Answer 22

factor out the w.

Answer 23

so yu get
w(whatever you get in the parenthesis)=0

Answer 24

w(-1^4-12^3-2196^2+15552)=0

Answer 25

no. the only thing that change is the exponents. they all go down by one.

Answer 26

w(-1^3-12^2-2196+15552)=0 is that what u mean?

Answer 27

no the w stay where they are.

Answer 28

so the first term is -w^3

Answer 29

-w^3-12^2-2196w+15552=0

Answer 30

all w's stay. even on the ^2

Answer 31

-w^3-12w^2-2196w+15552=0 That?

Answer 32

dont forget yur w( ) but keep factoring the polynomial.

Answer 33

w(-w^3-12w^2-2196w+15552)=0 But how can I factor more than that?

Answer 34

we can try factor by grouping right?

Answer 35

I don't know that method unless I call it something else..

Answer 36

its algebra 1 factoring.

Answer 37

so divide the exponents by w?

Answer 38

wait a min....

Answer 39

okay yeah
w(-w^3-12w^2)(-2196w+15552)=0
and factor out the parenthesises

Answer 40

Do I distribute the w first.

Answer 41

no. take the set and factor it

Answer 42

w(-w-12)(-2196+15552)=0 eh?

Answer 43

okay lets just work on the first set of the parenthesis. (-w^3-12w^2)

Answer 44

Ok, I'm not sure what to do if what I did before isn't right

Answer 45

yu should get
-w^2(w+12)

Answer 46

ah ok, that makes sense

Answer 47

can yu do the second term?

Answer 48

36(-61w+432) ?

Answer 49

right. now the -w^2 will be to the -36 so yu yuterms and -w^2-36 and(-61w+432) (w+12)

Answer 50

now do I combine them?

Answer 51

pretty much.but seperate them all by parenthesis.

Answer 52

-w^2-60w+408=0 ?

Answer 53

no.
w( -w^2-36)(-61w+432)(w+12)=0

Answer 54

got it?