Question

how do I find the zeros for y= 12x^2+8x-15 and rewrite it in intercept form?

Answer 1

factorize first

Answer 2

y = 12x^2 + 8x - 15

dy/dx = m = 24x + 8

y = mx + c

y = (24x + 8)x + c

We need to find c, so:

12x^2 + 8x - 15 = (24x + 8)x + c

12x^2 + 8x - 15 = 24x^2 + 8x + c

-12x^2 - 15 = c

Therefore the form is:

y = (24x + 8)x - (12x^2 + 15)

Expand:

y = 24x^2 + 8x - 12x^2 - 15

y = 12x^2 + 8x - 15 ... i dont know if i answered this correctly... was that your question??

Answer 3

No, but thanks anyways. I have to have it look something like this.
Ex: question: 2x^2+5x-3
answer: (2x-1)(x+3)

Answer 4

oooohhh.... im sorry!! but u have the answer?

Answer 5

Its fine. I have the answer to that question but I cannot figure out how to solve 12x^2+8x-15.

Answer 6

u made it look sooo much easier!:)

Answer 7

oh.. well i wish i could help, but i would probably just confuse you...:) sorry!!

Answer 8

Its just factoring and the example was an easier problem. I have others similar to it.
Ex: 18x^2+48+32
2(9x^2+24+16
2(3x+4)(3x+4) and the answer would be 2(3x+4)(3x+4)

Answer 9

Thanks anyways though, Kelly.

Answer 10

your welcome!