Question

If y = f(x) is the basic reciprocal square power function, then y=x

Answer 1

So, I'm guessing \[f(x) = \frac{1}{x^2} \]
In that case, \[ y = x\\\frac{1}{x^2} = x\\x^3 = 1\\x=\sqrt[3]{1} \]

Answer 2

its supposed to be y=x^???

Answer 3

\[y = f(x)\\y=\frac{1}{x^2}\\y=x^{-2}\]

Answer 4

i tried that before i posted it and it said that it was incorrect.

Answer 5

does anyone know?

Answer 6

Can you make sure you're giving us the correct problem? That should be correct.

Answer 7

it wants y=x^?

Answer 8

... and you tried entering -2?

Answer 9

yes i entered -2. thats what i thought the answer was, but i guess not

Answer 10

i keep trying it, but its not working