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How do I find the equation of f '(x) using the newton quotient equation. f(x) = |x-6|
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lim f(x+h) - f(x) x->0
f'(x)=lim [|(x+h)-6|-|x-6|]/h x->0
So does it end up at lim h/h h ->0 If that is so, would that be 1 or 0/0?
you need two cases, one for \(x>6\) and one for \(x<6\)
it is absolute value, right?
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ah, so I have to break it up into a piecewise function?
yes because \[f(x)= |x-6| = \left\{\begin{array}{rcc} -x+6 & \text{if} & x <x \\ x-6& \text{if} & x\geq 6 \end{array} \right.\]
in any case the answer you should get is simple, because these are just two line.. slope of first one is \(-1\) and slope of second one is \(1\)
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