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Mathematics 21 Online
OpenStudy (anonymous):

find line tangent to y=xcosx at point (pi, -pi)

OpenStudy (anonymous):

tangent is -1

OpenStudy (anonymous):

just typed y=-1 in. says incorrect

OpenStudy (anonymous):

the equation should be y = -x

OpenStudy (anonymous):

yep, ty.

OpenStudy (anonymous):

this is how I calculated it. y = xCosx is the function. taking it's derivative gives the slope to be dy/dx = cosx, which when evaluated at x =pi gives -1. now equation of line is y=mx+c, we know m=-1 and putting y = -pi and x = pi we get c =0. thus the equation of line tangent to the curve is y =-x

OpenStudy (anonymous):

ok

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