Question

How do I simplify ln(ln(2)+ sqrt((ln(2))^2+1))

Answer 1

\[\ln(\ln(2)+ \sqrt((\ln(2))^2+1))\]

Answer 2

@Algebraic! i'm sure you have a solution.. :)

Answer 3

sure it's written correctly?

Answer 4

i'm evaluating inverse sinh at ln(2)

Answer 5

maybe its like this?
ln[(ln(2)+ sqrt((ln(2))^2+1))]

Answer 6

\[\ln(\ln(2)+ \sqrt((\ln(2)^2+1))\]

Answer 7

ln[(ln(2)+ sqrt((ln(2))^2+1))]= 0.64704348

inverse of sinh (ln2)= 0.64704348

Answer 8

supposed to have an exact value.

Answer 9

doesn't

Answer 10

is it ln (2^2) ???

Answer 11

or (ln(2))^2

Answer 12

(ln(2))^2, my bad.

Answer 13

\[\ln(\ln(2)+ \sqrt((\ln(2))^2+1))\]

Answer 14

I don't think it can be simplified anymore further. I thought you could square root the (ln(2))^2 + 1 to give just ln2 +1

Answer 15

so the root is on... (ln2)^2 +1 ..

Answer 16

\[\sqrt{(\ln2)^2 +1} = 2\ln2 +1\]

Answer 17

??

Answer 18

no...

Answer 19

@Algebraic! \[\sqrt{(\ln2)^2 +1} = ??\]

Answer 20

@satellite73 any help?