Question

1) A rock thrown horizontally from the top of a
water tower lands 20.0 m from the base of the
tower. If the rock was initially thrown at a velocity
of 10.0 m/s,
a) how high is the water tower?
b)What is the final velocity of the rock?

Answer 1

dx = 20m
V1 = 10m/s
g = 9.8m/s^2
(delta-t) = 2 sec
dy = 19.6m

Answer 2

To get the answer for b), why do you use Vx with dy and acceleration in the y direction?

Answer 3

Find the final horizontal and vertical velocities!
can you do that?

Answer 4

When finding the horizontal velocity, what do we use?

Answer 5

The horizontal velocity remains constant throughout the motion!

Answer 6

so 10m/s?

Answer 7

yes! The final horizontal velocity will be same as initial horizontal velocity, i.e. 10 m/s

Now, can you find final vertical velocity?

Answer 8

how would you do that?

Answer 9

39.3m/s?

Answer 10

39.2*

Answer 11

nvm that's not right

Answer 12

the body is accelerating in vertical direction with an acceleration g and its initial vertical velocity is zero (since it was projected horizontally)..
So, you have the initial velocity, the acceleration and time.. You should be able to find the final velocity!
And show me the calculation, not the answer..
I am too lazy to do the calculation myself and check your answer.. But i can guide you!

Answer 13

actually, that makes sense to me, thanks :)