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Mathematics 15 Online
OpenStudy (anonymous):

State the vertical asymptote of the rational function.

OpenStudy (eyust707):

What number do you have to plug in for x to make the bottom part 0?

OpenStudy (anonymous):

Assume as follows. \[x^2 - 4 = 0\\ x^2 = 4\\ x = \pm\sqrt4 = \pm2\] Therefore f(x) has a vertical asymptote at... \[x = \pm2\]

OpenStudy (anonymous):

x = –9, x = 7 x = 9, x = –7 x = 2, x = –2 None

OpenStudy (anonymous):

The correct choice is there now select it.

OpenStudy (anonymous):

i dont know can you help me?

OpenStudy (anonymous):

I stated x = +- 2. Which option corresponds to that?

OpenStudy (anonymous):

x=2 x=-2 how did you get that?

OpenStudy (anonymous):

A vertical asymptote exists in a rational function where the denominator approaches zero. Take the denominator and find what values of x will cause it to be zero.

OpenStudy (anonymous):

when i plug in 2 and -2 on top it gives me -35 than what?

OpenStudy (anonymous):

u dont care about the top, u only care about the bottom! whichever set of numbers that gives u zero in the denominator is your vertical asymptote.

OpenStudy (anonymous):

oh okay

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