State the vertical asymptote of the rational function.
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OpenStudy (eyust707):
What number do you have to plug in for x to make the bottom part 0?
OpenStudy (anonymous):
Assume as follows.
\[x^2 - 4 = 0\\ x^2 = 4\\ x = \pm\sqrt4 = \pm2\]
Therefore f(x) has a vertical asymptote at... \[x = \pm2\]
OpenStudy (anonymous):
x = –9, x = 7
x = 9, x = –7
x = 2, x = –2
None
OpenStudy (anonymous):
The correct choice is there now select it.
OpenStudy (anonymous):
i dont know can you help me?
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OpenStudy (anonymous):
I stated x = +- 2. Which option corresponds to that?
OpenStudy (anonymous):
x=2 x=-2 how did you get that?
OpenStudy (anonymous):
A vertical asymptote exists in a rational function where the denominator approaches zero. Take the denominator and find what values of x will cause it to be zero.
OpenStudy (anonymous):
when i plug in 2 and -2 on top it gives me -35 than what?
OpenStudy (anonymous):
u dont care about the top, u only care about the bottom! whichever set of numbers that gives u zero in the denominator is your vertical asymptote.
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