Question

what is the general term of this sequence:

-1, 2, -3, 4, -5

Answer 1

is something like

\[-1 \times ( - \frac{n +1}{n})\] where n = 1, 2, 3, ......

given a 1st term of -1

Answer 2

that generates the terms -2, 3, -4, 5 etc.

Answer 3

isn't that wrong? for n=2 it is \[-1\times \left( \frac{ 2+1 }{ 2 } \right)\] which is 3/2

Answer 4

got it

\[T_{n} = (-1)^n \times n\]

Answer 5

lol... I looked for to much in the question... sorry

Answer 6

ah i found it out. it should be \[(-1^n)*-((n+1)/1^n)\]

Answer 7

that doesn;t work for n = 1

T1 = (-1^1)* -1(1 +1)/1^1

T1 = 2

you need T1 = -1

Answer 8

yeah i see that now. but the last one you gave me works. thanks :)

Answer 9

lol.. is was simpler than it looked..

Answer 10

yeah it was