Question

\[f(x)= \frac{ ax ^{3}+bx^{2}-13x+2c }{ x^{2}-2x+1 }, and \lim_{x \rightarrow 1}f(x) = 11\]
Find a,b,c

Answer 1

@hartnn

Answer 2

@AravindG

Answer 3

since the limit exist, x-1 is the factor of numerator
so 1 is the root.--->a+b+2c-13=0
since u have a factor of x-1 twice in the denominator, u need to use L'Hopitals twice and put x=1. so u have
3a+2b-13=0
and lastly,
6a+b=11
solve these three simultaneously, u'll find a,b,c.

Answer 4

right thanks

Answer 5

welcome :)

Answer 6

@Zekarias srry i was nt here