Question

given that α and β are the roots of the equation
x²= x+7

Answer 1

0 = x^2 - x - 7
0 = x(x - 1) - 7

Answer 2

prove that
\[(a) \frac{ 1 }{\alpha} =\frac{\alpha-1}{ 7}\]

Answer 3

\[x^2 - x - 7 = 0\]

Answer 4

go ahead an solve, see what you get

Answer 5

6 and 7, but that doesn't work in a proof...

Answer 6

ooops 7 and 8

Answer 7

since a is the root, u can write
a^2 = a+7
a^2-a=7
a(a-1)=7
a-1 = 7/a
1/a = (a-1)/7

Answer 8

a=alpha

Answer 9

a(a-1)=7
a-1 = 7/a<-------dividing both sides by 7
1/a = (a-1)/7<------dividing both sides by (a-1)

Answer 10

yes

Answer 11

He just used factor theorem.

Answer 12

U know factor theorem?

Answer 13

neither 7 nor 8 area solutions

Answer 14

plz solve part (b)
\[\alpha^{3} =8\alpha+7\]

Answer 15

a^2 = a+7
a^3 = a^2 + 7a
=a+7+7a
=8a+7

Answer 16

^ jobs done

Answer 17

thanks

Answer 18

did u understand ?