Question

HELP PLEASE!
EQUATION IS IN COMMENTS

Answer 1

x^2y-5xy+6y+7x^2-35x+42

Answer 2

solving for x?

Answer 3

factoring

Answer 4

xy(x-5)+6y+7x(x-5)+42=0

Answer 5

(xy+7x)(x-5)+(6y+42)=0
x(y+7)(x-5)+6(y+7)=0
{x(x-5)+6}(y+7)=0....i am not sure tho

Answer 6

@andriod09 does that help?

Answer 7

no, not really. but i have the answer.

Answer 8

hello solving for x
x(x-5)+6=0
x^2-5x+6=0
delta =1
x1=3 and x2=3

Answer 9

x2 =2

Answer 10

I AM NOT SOLVING FOR "X"!!! I AM FACTORING THE POLYNOMIAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 11

^^^^got so mad

Answer 12

your question is "HELP PLEASE!
EQUATION IS IN COMMENTS"

Answer 13

"andriod09 0
factoring
10 minutes agoDelete"

Answer 14

is it incomplete?

Answer 15

all i had to do is factor the polynomial. thats it. i already have the answer.

Answer 16

that's it

Answer 17

but its not the correct answer

Answer 18

then do it other way

Answer 19

the correct answer is:
(x-2)(x-3)(y+7)

Answer 20

dude factor my last equation...you will get this

Answer 21

(x^2-5x+6)(y+7)=0
(x-2)(x-3)(y+7)=0

Answer 22

no, your last equation as a quadratic equation, this is just a normal polynomial

Answer 23

{x(x-5)+6}(y+7)=0
{x^2-5x+6}(y+7)=0
(x^2-3x-2x+6)(y+7)=0
(x-2)(x-3)(y+7)=0 @Nicole<3Algebra can you help further

Answer 24

@andriod09 hope it is clear to you now?