Question

x sin y + cos 2y = cos y

Answer 1

nice equation....

Answer 2

I'm sorry I left out some stuff there I am trying to find dy/dx using implicit differentiation

Answer 3

Differentiate both sides with respect to x, then solve for dy/dx.

Answer 4

How would I go about that something like cos x y+cos 2y +sin x y + -sin y=-sin y?

Answer 5

I know i'm leaving something out but not sure what

Answer 6

Not sure what you are asking, could you be more specific?

Answer 7

So what you want to do is to solve the following equation for dy/dx:
\[ \frac{d}{dx}(x\sin{y}+\cos{2y})=\frac{d}{dx}\cos{y} \]

Answer 8

I am trying to find dy/dx using implicit differentiation for the equation x sin y+ cos 2y = cos y
was that more helpful?

Answer 9

So for the left side you have:
\[ \frac{d}{dx}(x\sin y+\cos 2y)=\frac{d}{dx}x\sin y+\frac{d}{dx}\cos 2y \\
= \sin y+x\cos(y)\frac{dy}{dx}-\sin(2y)*2\frac{dy}{dx}\]

Answer 10

Now just do the right side and solve for dy/dx like it's a normal equation.

Answer 11

Thanks for the help!

Answer 12

No problem! =)