Question

You roll a blue die and a yellow die. What is P(the sum of the dice is at least 6 | the blue die shows a 4)? Write fractions using the slash ( / ) key. Reduce fractions to their lowest terms.

Answer 1

Can someone help me with this please ): Or if you replied.... idk how to use this yet.

Answer 2

lol ok

Answer 3

Do you know how to do this?

Answer 4

yes

Answer 5

lets say the first die is the blue one

Answer 6

wow did i screw that up
first die is a 4!!

Answer 7

But it says, given that the blue die shows a 4, so wouldn't there be a 4 in each set?

Answer 8

lololol yeah it's all good (:

Answer 9

sorry
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

Answer 10

so you have six possibilities
of those six how many have a total that is greater than or equal to 6?

Answer 11

5.

Answer 12

right, so you have 6 equally likely choices of which 5 are what you want
answer is therefore \(\frac{5}{6}\)

Answer 13

oh, it's not 5/36?

Answer 14

hold the phone

Answer 15

HOLDING

Answer 16

your are TOLD that the first die is a 6 so you do not have 36 possibilities any more

Answer 17

"you are"

Answer 18

in other words, your "sample space' no longer has 36 elements in it. it only has 6

Answer 19

the slash means "given" as in "given the first die shows a 4"

Answer 20

The sum of the dice is at least 6... given that the blue die shows a 4. I thought that just meant you had to find how many would add up to 6 or higher given a 4, out of 36 possibilities.

Answer 21

\[P(A|B)\] read "the probability of A given B" i.e. you know B has occurred

Answer 22

given means you know it happened
that is why i made the list above (got it right on like the fourth try) so we could count how many were in it and of those count how many had a total 6 or higher

Answer 23

Oh okayy.

Answer 24

Thank you!

Answer 25

example: probability you roll a total of 6 GIVEN you have doubles
count (1,1)(2,2),(3,3),(4,4),(5,5),(6,6) and of those one (3,3) has a total of 6 so that probability is \(\frac{1}{6}\)

yw