Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

xsqrt(x)+xsqrt(x)

OpenStudy (anonymous):

does it look like 2x sqrtx

Parth (parthkohli):

Yes.

OpenStudy (anonymous):

\[x \sqrt x+ x \sqrt x= 2x \sqrt x\]

OpenStudy (anonymous):

add them up and what do you think it is?

OpenStudy (anonymous):

\[x \sqrt{x}+x \sqrt{x}\]

OpenStudy (anonymous):

cool

OpenStudy (anonymous):

so whats that equal?

OpenStudy (anonymous):

2xsqrt(x)^2?

OpenStudy (anonymous):

obviously

OpenStudy (anonymous):

thats wrong

OpenStudy (anonymous):

the book is telling me it equals 2x(x)^3/2

OpenStudy (anonymous):

two radicals added together can't turn into ^2

OpenStudy (anonymous):

yeah because you have to get ride of the square roots so theres your answer

OpenStudy (anonymous):

how does that work?

OpenStudy (anonymous):

there you go

OpenStudy (anonymous):

isnt x^3/2 x^m/n?

OpenStudy (anonymous):

\[(x^2)^{1/2*3}= x^{2*\frac{ 1 }{ 2 }*3}=x^3\]

OpenStudy (anonymous):

where is x^2 coming from?

OpenStudy (anonymous):

and * 3

OpenStudy (anonymous):

it was in your question\[\sqrt[3]{x^2}\]

OpenStudy (anonymous):

no that was a mistake

OpenStudy (anonymous):

\[\sqrt{x}+\sqrt{x}\]

OpenStudy (anonymous):

why is that x^3/2

OpenStudy (anonymous):

|dw:1348241313310:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!