Question

One more additional question
How many terms of the series 9 + 0.1 + 0.01 + 0.001 + ... must be taken so that the sum of infinity exceeds the\[n^{th}\] partial sum by \[\frac{ 1 }{ 9\times10^{7} }\]

Answer 1

choices
A) 6 B) 7 C)9 D)11 E) None

Answer 2

I think its 1+0.1+0.01+0.001+...

Answer 3

nope, It just like it.

Answer 4

What is partial sum

Answer 5

the sum of the series up to n terms

Answer 6

Oh..... I just got the question/

Answer 7

7

Answer 8

U have to take less than 7.95 terms

Answer 9

You are triked

Answer 10

???

Answer 11

Isnt Sum of infinity =82/9

Answer 12

Read the question carefully

Answer 13

Oh forgot to add 1

Answer 14

right?

Answer 15

yape

Answer 16

\[S _{\infty} = S_{n} + \frac{ 1 }{ 9\times10^{7} }\]
\[9+\frac{ \frac{ 1 }{ 10 }(1-\frac{ 1 }{ 10^{\infty} }) }{ 1-\frac{ 1 }{ 10 } } =9+\frac{ \frac{ 1 }{ 10 }(1-\frac{ 1 }{ 10^{n-1} }) }{ 1-\frac{ 1 }{ 10 } }+\frac{ 1 }{ 9\times10^{7} }\]

Answer 17

So, Is the answer none.

Answer 18

yes