derivative of x^2(2x-1)^3
Is that\[x ^{2}(2x-1)^{3}\] ?
yes
Ok, You need to take the first factor times the derivative of the second + the second factor times the derivative of the first.
chain rule?
The chain comes into effect when taking the derivative of the second factor. The overall rule is the addition rule
6(2x-1)*2 is what i get when doing the chain rule. mind just giving me the answer and i can see how you got it? :P
ok, wait a sec.
[(2x-1)^3]2x + (x^2)3[(2x-1)^2]2
There are 2 concepts going on here. First is the addition rule. After the "+", the chain rule comes into play on that half.
are you sure this cant be solved just using the chain rule?
oo hmm. i see. you used product rule too didnt you?
The chain rule applies to the second factor, (2x-1)^3, where you take the outer and then the inner derivative. What you have going on here is first a derivative of a product, so you have to handle that idea first.
ye, i get it now. thx
You're getting it now. It's like doing exponentiation before multiplication.
ty
thx for medal and good luck in your studies.
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