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Mathematics 6 Online
OpenStudy (anonymous):

derivative of x^2(2x-1)^3

OpenStudy (anonymous):

Is that\[x ^{2}(2x-1)^{3}\] ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Ok, You need to take the first factor times the derivative of the second + the second factor times the derivative of the first.

OpenStudy (anonymous):

chain rule?

OpenStudy (anonymous):

The chain comes into effect when taking the derivative of the second factor. The overall rule is the addition rule

OpenStudy (anonymous):

6(2x-1)*2 is what i get when doing the chain rule. mind just giving me the answer and i can see how you got it? :P

OpenStudy (anonymous):

ok, wait a sec.

OpenStudy (anonymous):

[(2x-1)^3]2x + (x^2)3[(2x-1)^2]2

OpenStudy (anonymous):

There are 2 concepts going on here. First is the addition rule. After the "+", the chain rule comes into play on that half.

OpenStudy (anonymous):

are you sure this cant be solved just using the chain rule?

OpenStudy (anonymous):

oo hmm. i see. you used product rule too didnt you?

OpenStudy (anonymous):

The chain rule applies to the second factor, (2x-1)^3, where you take the outer and then the inner derivative. What you have going on here is first a derivative of a product, so you have to handle that idea first.

OpenStudy (anonymous):

ye, i get it now. thx

OpenStudy (anonymous):

You're getting it now. It's like doing exponentiation before multiplication.

OpenStudy (anonymous):

ty

OpenStudy (anonymous):

thx for medal and good luck in your studies.

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