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\[\lim_{(x,y) \rightarrow (0,0)} (x^2y^2)/(x^2+y^2)\]
Would it just be 0...?
well i can summarize it by putting it into table format if the x and y values equal: -3=4.5 -2= 2 -1 = 1/2 -1/2 = 1/8 -1/4 = 1/32 1/4 =1/32 1/2 = 1/8 1 = 1/2 2 = 2 3 = 4/5
The closer the numbers get to (0,0) the larger the denominator gets in the answers. So the limit of x,y -> 0,0 is 0.
@m.auld64 Any questions? or you just sitting there doing nothing.. =P
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