Question

(1-cotx)/(tanx-1)

Answer 1

write cot x as cos x/sin x
tan x as sin x/ cos x

Answer 2

or u can just write cot x = 1/ tan x and simplify.

Answer 3

or you can just divide...

Answer 4

hello
(1-cosx/sinx)/(1-sinx/cosx)=
((sinx-cosx)/sinx)×((cosx)/(cosx-sinx))=
-cosx/sinx = -cotanx

Answer 5

just one typo:
it will be
(1-cosx/sinx)/(sinx/cosx-1)=
((sinx-cosx)/sinx)×((cosx)/(sin x -cos x))=
cosx/sinx = cot x

cot x is your final answer.....