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OpenStudy (anonymous):
Find the equation of straight line passing through point (4,5) and equally inclined to the lines 3x = 4y+7 and 5y = 12x+6
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OpenStudy (anonymous):
find the angular bisector of the lines that passes through (4,5)
OpenStudy (anonymous):
7y = 9x -1
OpenStudy (anonymous):
howwwwww
OpenStudy (anonymous):
@lgbasallote @waterineyes
OpenStudy (anonymous):
clearly m1 = 3/4 and m2= 12/5 Let m be the slope of line bisceting the angle between two lines. tan A = (m-3/4) / (1+[3/4]m) = (4m - 3) /(4 + 3m) tan A = (12/5 - m) / (1+[12/5]m) = 12 -5m / 5+12m Equating we get m = 9/7 With a point (4,5) and slope m = 9/7
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OpenStudy (anonymous):
Equation of line will be 7y = 9x -1
OpenStudy (anonymous):
lol i am dumb :|
OpenStudy (anonymous):
thanx
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