sum of the areas of two squares is 468msquare. if the diff of there perimeter is 24m . formulate the quad eq to find the sides of the squares? plz.................. help

Question

anonymous · Answer

x^2 + y^2 = 468
and
4x + 4y = 24 

can you solve now?

anonymous · Answer

$$x^2 + y^2 = 468$$
$$4x + 4y = 24  $$

anonymous · Answer

can you solve now?

anonymous · Answer

oh ya m sry, it says difference, right!1
it must be a minus sign in between
thats the difference of perimeters ;)

anonymous · Answer

ha... then x^2 +y^2= 468

4(x+y)=24

x+y=6

squaring on both sides

x^2 + y^2 +2xy= 36

2xy= 36 - (468)

2xy= -432

xy=-216

x(6-x)=-216

6x-x^2=-216

x^2-6x-216=0

solve it for x and put it in the above equation to get y.... the values may differ with actual but the process is correct i hope...