Question

Limits

lim_{x rightarrow infty } sqrt{x ^{2} + x} - sqrt{x ^{2} + 1}

Answer 1

http://www.wolframalpha.com/input/?i=lim+%28sqrt%28x%5E2%2Bx%29-sqrt%28x%5E2%2B1%29%2Cx%2Cinfinity%29
Click on show steps to see the steps.. Wolfram is your best friend (for the most problems)...

Answer 2

I do not understand with this form

Answer 3

what form? indeterminate form?

Answer 4

can u use L'Hopitals ?

Answer 5

no @hartnn

Answer 6

yes @bahrom7893

Answer 7

Ohhhhhh i see

Answer 8

try this, put x=1/y
as x->infinity, y->0

Answer 9

u will get :
\(\large \frac{\sqrt{1+y}-\sqrt{1+y^2}}{y}\)
now multiply by conjugate.

Answer 10

are u trying ? @Muskan or should i give further steps ?

Answer 11

give me setps

Answer 12

first, did u get my substitution ? and how i got that function in y ?

Answer 13

yes

Answer 14

\(\large \frac{\sqrt{1+y}-\sqrt{1+y^2}}{y}\quad \large \frac{\sqrt{1+y}
+\sqrt{1+y^2}}{\sqrt{1+y}
+\sqrt{1+y^2}}=\frac{1+y-1+y^2}{y*(\sqrt{1+y}
+\sqrt{1+y^2})}\)
can u solve further ?