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Mathematics 7 Online
OpenStudy (anonymous):

Find the ratio of the area of triangle XBY to the area of triangle ABC for the given measurements, if LINE XY is PARALLEL TO LINE AC

OpenStudy (anonymous):

BY = 3, YC = 2

OpenStudy (anonymous):

@tcarroll010 Some help please?

OpenStudy (anonymous):

thats a ratio of 3:5?

OpenStudy (anonymous):

Lol, is it?

OpenStudy (anonymous):

|dw:1348331164200:dw|

OpenStudy (anonymous):

Isn't that 5:2?

OpenStudy (anonymous):

then the area of the top one is 9 and the bigger triangle is 25

OpenStudy (anonymous):

\[\frac{ 3^{2} }{ 5^{2}}\]

OpenStudy (anonymous):

9/25

OpenStudy (anonymous):

|dw:1348331474528:dw|

OpenStudy (anonymous):

I'm sorry i don't understand how you are getting this Mind running me through the first steps?

OpenStudy (anonymous):

|dw:1348331540707:dw|

OpenStudy (anonymous):

|dw:1348331623710:dw|

OpenStudy (anonymous):

then the pictures above show them on top of each other

OpenStudy (anonymous):

How did you get 10?

OpenStudy (anonymous):

The ratio of the sides is equal if there are parallel lines

OpenStudy (anonymous):

because they are similar

OpenStudy (anonymous):

because you are just extending the sides of the smaller one yes?

OpenStudy (anonymous):

Oh yes

OpenStudy (anonymous):

So the scale used to increase the smaller one is 3:5

OpenStudy (anonymous):

so i made one of the sides = 6 and that is an easy ratio to do

OpenStudy (anonymous):

i just multipled the ratio by 2

OpenStudy (anonymous):

so 6:10

OpenStudy (anonymous):

Ohhhh. Okay

OpenStudy (anonymous):

and since area is basically multiplying the ratio of the sides

OpenStudy (anonymous):

3/5 * 3/5

OpenStudy (anonymous):

\[\frac{ 3^2 }{ 5^2 }\]

OpenStudy (anonymous):

9/25 is the answer

OpenStudy (anonymous):

9/25? not 9:25?

OpenStudy (anonymous):

same thing

OpenStudy (anonymous):

Ok cool

OpenStudy (anonymous):

What if BY = 2, BC = 4?

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