Mathematics
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OpenStudy (anonymous):
Find the ratio of the area of triangle XBY to the area of triangle ABC for the given measurements, if LINE XY is PARALLEL TO LINE AC
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OpenStudy (anonymous):
BY = 3, YC = 2
OpenStudy (anonymous):
@tcarroll010 Some help please?
OpenStudy (anonymous):
thats a ratio of 3:5?
OpenStudy (anonymous):
Lol, is it?
OpenStudy (anonymous):
|dw:1348331164200:dw|
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OpenStudy (anonymous):
Isn't that 5:2?
OpenStudy (anonymous):
then the area of the top one is 9 and the bigger triangle is 25
OpenStudy (anonymous):
\[\frac{ 3^{2} }{ 5^{2}}\]
OpenStudy (anonymous):
9/25
OpenStudy (anonymous):
|dw:1348331474528:dw|
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OpenStudy (anonymous):
I'm sorry i don't understand how you are getting this
Mind running me through the first steps?
OpenStudy (anonymous):
|dw:1348331540707:dw|
OpenStudy (anonymous):
|dw:1348331623710:dw|
OpenStudy (anonymous):
then the pictures above show them on top of each other
OpenStudy (anonymous):
How did you get 10?
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OpenStudy (anonymous):
The ratio of the sides is equal if there are parallel lines
OpenStudy (anonymous):
because they are similar
OpenStudy (anonymous):
because you are just extending the sides of the smaller one yes?
OpenStudy (anonymous):
Oh yes
OpenStudy (anonymous):
So the scale used to increase the smaller one is 3:5
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OpenStudy (anonymous):
so i made one of the sides = 6 and that is an easy ratio to do
OpenStudy (anonymous):
i just multipled the ratio by 2
OpenStudy (anonymous):
so 6:10
OpenStudy (anonymous):
Ohhhh. Okay
OpenStudy (anonymous):
and since area is basically multiplying the ratio of the sides
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OpenStudy (anonymous):
3/5 * 3/5
OpenStudy (anonymous):
\[\frac{ 3^2 }{ 5^2 }\]
OpenStudy (anonymous):
9/25 is the answer
OpenStudy (anonymous):
9/25?
not 9:25?
OpenStudy (anonymous):
same thing
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OpenStudy (anonymous):
Ok cool
OpenStudy (anonymous):
What if BY = 2, BC = 4?