Question

please answer

Answer 1

Hi, I answered :)

Answer 2

\[(\sin \frac{ 1 }{ 2 }x - \cos \frac{ 1 }{ 2 }x)^{2}\]

Answer 3

haha.. lol jiji :))

Answer 4

use (a-b)^2 = a^2 + b^2 - 2ab

Answer 5

let a=1/x

then (sina-cosa)^2 = 1-sin2a = 1-sin 2* x/2 = 1-sinx

simple :))))))))

Answer 6

sin^2 x/2 + cos^2 x/2 - 2sinx/2 cosx/2

sin^2 x/2 + cos^2 x/2 = 1

2sinx/2 cosx/2 = sin 2 x/2

use this

Answer 7

So

sin^2 x/2 + cos^2 x/2 - 2sinx/2 cosx/2 =

1 - sinx

Answer 8

Hmm...Why not trying to get the asker involved in his own questions?
It isn't helping if you do all the work.

Answer 9

@sriramkumar do u mean a=(1/2)x ??
@myininaya i'm also answering the question step by step.. don't worry.. they helped me a lot !! :))
thanks for the help again!! :))

Answer 10

yes... @eroshea

Answer 11

its a= x/2

Answer 12

ok.. so you also used double identity ?? i didn't taught of it.. :)) thanks men

Answer 13

sorry, i dont know about the names, becoz i didnt ever cared them... @eroshea

Answer 14

owh.. my bad x) but you helped a lot!

Answer 15

ha... @eroshea welcome :)))))))))