Please help me solve this differential equation yI=(1-x)y2 + (2x-1) y-1 given y͵=1

Question

anonymous · Answer

lol im learning this right now...

turingtest · Answer

$$y'=(1-x)y^2+(2x-1)y-1\text{ given }y=1$$correct?
are you doing Laplace right now?

turingtest · Answer

$$y'=(1-x)y^2+(2x-1)y-1\text{ given }y(0)=1$$and what do you mean y=1, do you mean this^

nastech · Answer

no, Bernoulli and Riccati's equations

turingtest · Answer

I don't know Riccati and I have to review Bernoulli...

turingtest · Answer

do I have the problem right?$$y'=(1-x)y^2+(2x-1)y-1\text{ given }y(0)=1$$

turingtest · Answer

or is it$$y'=(1-x)y^2+(2x-1)y^{-1}\text{ given }y(0)=1$$

anonymous · Answer

divide the original equation by highest power of Y, example if we have a y^2 term we divide it by Y^2
 then rewrite it, let 1/y= K OR variable of your choice
sub that in the equation and that will give you a hint how to proceed further

anonymous · Answer

must say that if you have chosen 1/y= k, then make sure you find k',