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Mathematics 17 Online
OpenStudy (anonymous):

In the figure above, the small square is inscribed in the circle, which is inscribed in the large square. What is the ratio of the area of the large square to the area of the small square?

OpenStudy (anonymous):

tips?

OpenStudy (phi):

label the side of the small circle s notice its diagonal is s* sqrt(2) isn't that the width of the big square?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the diagonal of the small square?

OpenStudy (anonymous):

the diagonal of the small square is the square root of 2

OpenStudy (phi):

the diagonal of the small square is the diameter of the circle

OpenStudy (anonymous):

yeah...

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

you are right

OpenStudy (anonymous):

so

OpenStudy (anonymous):

2:square root of 2?

OpenStudy (phi):

so if the small square has side s and area s^2 the diagonal is s*sqrt(2) = side of big square. area is s^2*2

OpenStudy (anonymous):

so

OpenStudy (anonymous):

the small square has an area of 2

OpenStudy (anonymous):

and the big square has an area of 4?

OpenStudy (phi):

I would use s for the side of the small square

OpenStudy (anonymous):

so

OpenStudy (anonymous):

4:2

OpenStudy (phi):

now write down its area: s^2 write down its diagonal: s*sqrt(2)

OpenStudy (anonymous):

ty

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