In the figure above, the small square is inscribed
in the circle, which is inscribed in the large
square. What is the ratio of the area of the large
square to the area of the small square?
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OpenStudy (anonymous):
tips?
OpenStudy (phi):
label the side of the small circle s
notice its diagonal is s* sqrt(2)
isn't that the width of the big square?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
the diagonal of the small square?
OpenStudy (anonymous):
the diagonal of the small square is the square root of 2
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OpenStudy (phi):
the diagonal of the small square is the diameter of the circle
OpenStudy (anonymous):
yeah...
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
you are right
OpenStudy (anonymous):
so
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OpenStudy (anonymous):
2:square root of 2?
OpenStudy (phi):
so if the small square has side s and area s^2
the diagonal is s*sqrt(2) = side of big square. area is s^2*2
OpenStudy (anonymous):
so
OpenStudy (anonymous):
the small square has an area of 2
OpenStudy (anonymous):
and the big square has an area of 4?
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OpenStudy (phi):
I would use s for the side of the small square
OpenStudy (anonymous):
so
OpenStudy (anonymous):
4:2
OpenStudy (phi):
now write down its area: s^2
write down its diagonal: s*sqrt(2)