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Mathematics 8 Online
OpenStudy (anonymous):

Mary measures the weights of five newly hatched pythons in ounces. John converts Mary’s measurements to grams. There are 28.35 grams in an ounce. Here are Mary’s results: Python 1 2 3 4 5 Mary 1.13 oz 1.02 oz 1.23 oz 1.06 oz 1.16 oz Show how to calculate the mean and standard deviation of John’s weights.

jimthompson5910 (jim_thompson5910):

mean = (add up the weights)/5 to find the standard deviation, it's best to use a calculator (since the process is a bit tedious)

OpenStudy (anonymous):

hi I'm here now. @jim_thompson5910

jimthompson5910 (jim_thompson5910):

alright, did you manage to get anywhere with this problem?

OpenStudy (anonymous):

Um i think that the first step would be to convert the units

OpenStudy (anonymous):

to grams

OpenStudy (anonymous):

so would i multiply each by 28.35 to find johns measurements in grams?

jimthompson5910 (jim_thompson5910):

you are correct, what do you get when you do this?

OpenStudy (anonymous):

i get:

OpenStudy (anonymous):

| 32.04 | 28.92 | 34.87 | 30.1 | 32.89

OpenStudy (anonymous):

is that right

jimthompson5910 (jim_thompson5910):

it is, I'm getting this 32.0355 grams, 28.917 grams, 34.8705 grams, 30.051 grams, 32.886 grams, but that's basically what you have (you just rounded in different places)

OpenStudy (anonymous):

and from those i found a mean of 31.77

jimthompson5910 (jim_thompson5910):

one sec

OpenStudy (anonymous):

Ok cool

jimthompson5910 (jim_thompson5910):

I'm getting mean = 31.752 so again, you're close

OpenStudy (anonymous):

Ok should I just keep mine?

jimthompson5910 (jim_thompson5910):

You added up all the weights (in grams) and divided by 5 right?

OpenStudy (anonymous):

yes

jimthompson5910 (jim_thompson5910):

let me use your data set, one sec

OpenStudy (anonymous):

ok so now i do the standard deviation by : (32.04-31.77)^2 + (etc.. ) for all 5 then divide by 5 right to find st deviation?

jimthompson5910 (jim_thompson5910):

using your data set, I get 31.764 so it's closer

jimthompson5910 (jim_thompson5910):

yes, subtract the mean from each data value, then square each difference, then add up the differences

OpenStudy (anonymous):

ok let me do that then tell what i got

jimthompson5910 (jim_thompson5910):

then you divide by 4 since you're finding the sample standard deviation most likely

jimthompson5910 (jim_thompson5910):

last step is to take the square root

OpenStudy (anonymous):

oh i divide by 4 then?

jimthompson5910 (jim_thompson5910):

yes, when you're finding the sample standard deviation

OpenStudy (anonymous):

i got .0729 + 8.1225 + 9.61 + 2.7889 + 1.2544

OpenStudy (anonymous):

which is 21.8487.. is that right? and how do u know if its sample or population

jimthompson5910 (jim_thompson5910):

well for the most part, I think you're dealing with a sample (since you can't measure the entire population of every snake's egg), so that's why I think you're finding the sample standard deviation

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

what about my value

jimthompson5910 (jim_thompson5910):

usually in statistics, you're never going to be able to count/measure everything in the population, which is why you turn to the sample

jimthompson5910 (jim_thompson5910):

let me check

OpenStudy (anonymous):

ok!

OpenStudy (anonymous):

i found the standard deviation to be 1.169

OpenStudy (anonymous):

and the mean 21.8487. i rounded

jimthompson5910 (jim_thompson5910):

ok just to make things clear, you're using the data set 32.04, 28.92, 34.87, 30.1, 32.89 correct?

OpenStudy (anonymous):

yes

jimthompson5910 (jim_thompson5910):

using that data set, I'm getting 2.33712002259192

OpenStudy (anonymous):

for the mean?

jimthompson5910 (jim_thompson5910):

sample standard deviation

OpenStudy (anonymous):

oh ok what did u get the mean to be

jimthompson5910 (jim_thompson5910):

31.764

jimthompson5910 (jim_thompson5910):

(32.04+28.92+34.87+30.1+32.89)/5 158.82/5 31.764

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

did you get that? or something close to that?

OpenStudy (anonymous):

same! so my answer would be MEAN = 31.764 ; sample standard deviation = 2.33712002259192, or 2.34

jimthompson5910 (jim_thompson5910):

yes, that's what I would write

OpenStudy (anonymous):

can u check this prob for me? i already did it, i just want to see if you could check it

jimthompson5910 (jim_thompson5910):

go with 2.34 since it's shorter

jimthompson5910 (jim_thompson5910):

ok

OpenStudy (anonymous):

Mary measures the weights of five newly hatched pythons in ounces. John converts Mary’s measurements to grams. There are 28.35 grams in an ounce. Here are Mary’s results: Python 1 2 3 4 5 Mary 1.13 oz 1.02 oz 1.23 oz 1.06 oz 1.16 oz Calculate the mean and standard deviation of Mary’s measurements using the formula for each.

jimthompson5910 (jim_thompson5910):

same problem?

OpenStudy (anonymous):

my answer: The mean of Mary's measurements is 1.12. Knowing this, we can find the standard deviation. The standard deviation would be 0.074... sq.rt * (1.13 - 1.12)^2 + (1.02 - 1.12)^2 + (1.23 - 1.12)^2 + (1.06 - 1.12)^2 + (1.16 - 1.12)^2] / 5 -->.074

jimthompson5910 (jim_thompson5910):

oh ok nvm

jimthompson5910 (jim_thompson5910):

no, you're dividing by 4, not 5

OpenStudy (anonymous):

oh really?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

then can you see if my values are all correct, that way i can just divide it by 4 so i don't have to start over

OpenStudy (anonymous):

but my mean is right, correct? added them then divided by 5

jimthompson5910 (jim_thompson5910):

yes, the mean is add them up, divide by 5

OpenStudy (anonymous):

ok so my mean is right?

OpenStudy (anonymous):

now for the standard deviation..

jimthompson5910 (jim_thompson5910):

but why are you using Mary's measurements (in oz) when you're supposed to use John's measurements (in grams)

OpenStudy (anonymous):

this question is different. it says to use marys

jimthompson5910 (jim_thompson5910):

oh ok

OpenStudy (anonymous):

this one says Calculate the mean and standard deviation of Mary’s measurements using the formula for each.

jimthompson5910 (jim_thompson5910):

let me check

jimthompson5910 (jim_thompson5910):

i gotcha

OpenStudy (anonymous):

can u help me with finding standard deviation for this prob? i know that u divide by 4 now

OpenStudy (anonymous):

oh and my mean is correct then right

jimthompson5910 (jim_thompson5910):

your mean of 1.12 is correct

OpenStudy (anonymous):

ok so now to find standard deviation? i try doing it on my calculator and i keep getting E's

OpenStudy (anonymous):

can u help

jimthompson5910 (jim_thompson5910):

sure, the E's mean some error is occurring, not sure what error though...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i know the formula just need help solving it since my calc won't work

jimthompson5910 (jim_thompson5910):

one sec

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

You type in this ((1.13-1.12)^2+(1.02-1.12)^2+(1.23-1.12)^2+(1.06-1.12)^2+(1.16-1.12)^2)/4 to get this 0.00685 then you take the square root of that to get the final answer 0.08276472678623 So the sample standard deviation of Mary's measurements is roughly 0.08276472678623

OpenStudy (anonymous):

thank you so much

jimthompson5910 (jim_thompson5910):

np

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