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Mathematics 17 Online
OpenStudy (3psilon):

How would you solve this SAT problem ? Image attached

OpenStudy (3psilon):

OpenStudy (3psilon):

I felt like my way was tedious and there's a faster way to do it.

OpenStudy (anonymous):

\[\text{If }x+\frac1x\text{ is an integer, then that requires }x\text{ and }\frac1x\text{ are integers.}\\\frac1x\text{is only an integer for }x=\pm1\text{ if }x\text{ need be an integer}.\\ \text{Therefore }t\text{ is either...}\\ \ \ \ \nabla(1)=1+1=2\\ \ \ \ \nabla(-1)=-1-1=-2\]

OpenStudy (3psilon):

Wow great explaination @oldrin.bataku ! Thank you!

OpenStudy (3psilon):

Sometimes I fail to see logical things like that in the midst of the moment

OpenStudy (anonymous):

plz correct me if iam wrong \[\frac{ x ^{2}+1 }{ x }=t\] hence if we see the quadratic equation then we would find that the value of t would assume the role of b in the formula\[d=b^{2}-4ac\] as \[d \ge0\] so \[b ^{2}\ge4ac\] as a=1 c=1 so\[b ^{2}\ge4\] so i feel that -3 could also be the answer

OpenStudy (anonymous):

That's not a quadratic.

OpenStudy (anonymous):

why not

OpenStudy (anonymous):

@oldrin.bataku plz illustrate

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