Consider the function f(x) = 1/3x+ 2 Use function composition to show that f(x) and g(x) are inverses of each other.
where is g(x) ? or u need to find it ?
need to find it. @hartnn
so let y= 1/3x+2 exchange x and y x=1/3y+2 can u find y in terms of x now ?
is it 3x-6?
@hartnn
yes. that is g(x). now find f(g(x))
1/3 (3x-6)+2 = x-2+2=x ? @hartnn
or is it 1/3(3x-6)+2=3(1/3x+2)-6 ?
good work :) since f(g(x))=x u have verified that f and g are inverse of each other. also prove that g(f(x)) = x
wait which one was correct? the first one i said or the second. ?
first.
ok. so now how do i graph this?
I have to draw the graphs of f(x) and g(x) on the same coordinate plane.
f(x)=y=1/3x+2 put x=0, y=? put y=0,x=?
put x = 0, y= 1/3?
Im not sure... @hartnn
put x=0 y=1/3 x + 2 y=0+2 y=2. ok?
ok so 0,2? and 0,-6?
those are the coordinates?
0,2 is correct (-6,0)
ok so (0,2) and (-6,0)
i draw this on the x-axis? or y axis?
yup, plot those points. and join them by straight line..
(0,2) will lie on y axis. (-6,0) will lie on x-axis
the -6 gets a closed circle and the 2 is open right?
circle ?
never mind. that's for a different one :D THANKS FOR YOUR HELP!
how do i eXPLAINE how my grapgh shows that the functions are inverses of each other?
sorry for late reply. u can verify that f and g are inverses of each other by seeing that when f is reflected over line y=x , we get g. here's the plots: http://www.wolframalpha.com/input/?i=plot+x%2F3%2B2++and+3x-6+and+x
u asked same question @lavalava did u get all 3 parts ?
@Riza still any doubts ?
@hartnn no sir thanks
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