Prove by M.I. that (x+y)^n - x^n - y^n is divisible by xy(x+y). i am stuck in xyN(x+y)^2 + yx^k + xy^k what can i do next? thx.
or is there a simple and quick method to do this?
you sure thats right ? i guess n=2 doesnt work..
@shubhamsrg the question is actually just to prove that (x+y)^n - x^n - y^n is divisible by xy(x+y)..(by factor theorem) but i thought it may also be prove by M.I. so i wanted to try. We can't do it by M.I.??
I don't think you can with induction. induction is with single variable I think. I have never done it with more than one variable, note we need to show its true for n = 1. how would you do this? I could be wrong...
also, induction only shows when the independent variable is a natural.
when n = 1, (x+y) - x - y = 0 which is divisible by xy(x+y) can it be like this?
ahh yeah. But do you need to show this is true for all numbers or just the natural numbers?
for natural numbers
there are some M.I. problems in my book that include both x and y eg prove x^n - y^n is divisible by x-y
cool cool, I'm playing with it on paper....hope i can see the "trick"
thanks :)
hmm tricky... i cant figure out where to use the hypothesis...
yea..i deliberately make it as (x+y) [(x+y)^k + x^k + y^k] - x^(k+1) - y^(k+1) but i ended up with xyN(x+y)^2 + yx^k + xy^k... dont know what to do next...
I think WHEN n is even then (x+y)^n - x^n - y^n is not divisible by xy(x+y)...
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