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Chemistry 12 Online
OpenStudy (anonymous):

finding mass?

OpenStudy (unklerhaukus):

\[M_{\text{Mg}}=24.3 [\text{g}/{\text {mol}}]\] \[N_A=6.022\times10^{23} [\text{molecules}/{\text {mol}}]\]

OpenStudy (anonymous):

its 10^24 my bad

OpenStudy (unklerhaukus):

so you have \[6.98 × 10^{24}[\text{molecules}]\]

OpenStudy (unklerhaukus):

so lets find the number of moles you have \[\frac{6.98 × 10^{24}[\text{molecules}]}{ 6.022\times10^{23} [\text{molecules}/{\text {mol}}]}=\]

OpenStudy (anonymous):

how much?

OpenStudy (unklerhaukus):

how many moles is this?

OpenStudy (unklerhaukus):

its a bit more than 10 moles

OpenStudy (unklerhaukus):

now multiplying by 24 g/mol, we get almost 300 grams

OpenStudy (anonymous):

thank you very much

OpenStudy (unklerhaukus):

how many grams did you get?

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