An urn contains 4 black balls and 6 white balls. What is the probability of getting 1 black ball and 1 white ball on two consecutive draws from the urn?
is the solution to this 4/10 * 6/9 ?
yup.
a strange feeling tells me there's more to it...
hmm...i don't think so, though...
if they were not replaced....
if they were replaced then 4/10 * 6/10
well how do you know if it was replaced based on this kind of wording?
u don't.Question unclear.
it's not unclear. i think it's understood that you don't replace the ball.
i do too
but i still feel it's not as simple as this...
then its 4/10 * 6/9
It is this easy @Igbasallote :)
it is what it is-Simple. You're getting too worked up over nothing.
it was a question from a board exam back in '96 after all...so it could be a trick
lol
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