An urn contains 4 black balls and 6 white balls. What is the probability of getting 1 black ball and 1 white ball on two consecutive draws from the urn?

Question

lgbasallote · Answer

is the solution to this 4/10 * 6/9 ?

anonymous · Answer

yup.

lgbasallote · Answer

a strange feeling tells me there's more to it...

anonymous · Answer

hmm...i don't think so, though...

hartnn · Answer

if they were not replaced....

hartnn · Answer

if they were replaced then 4/10 * 6/10

lgbasallote · Answer

well how do you know if it was replaced based on this kind of wording?

hartnn · Answer

u don't.Question unclear.

anonymous · Answer

it's not unclear. i think it's understood that you don't replace the ball.

lgbasallote · Answer

i do too

lgbasallote · Answer

but i still feel it's not as simple as this...

hartnn · Answer

then its  4/10 * 6/9

anonymous · Answer

It is this easy @Igbasallote 
:)

anonymous · Answer

it is what it is-Simple. You're getting too worked up over nothing.

lgbasallote · Answer

it was a question from a board exam back in '96 after all...so it could be a trick

anonymous · Answer

lol