Question

In the diagram, PSR and RTQ are right angled triangles. If TR = 8 cm, Find the area of PQRS.

Answer 1

assuming t is the intersection of PR and Q(T?):
the line PR is 18+8, 26cm
thus the area of triangle PQR is 1/2bh, = (1/2) x 26 x 12 = 156

area of triangle PSR is 1/2bh, = (1/2) x 26 x 10 = 130

area of total PSQR = 130 + 156 = 286

Answer 2

For the triangle psr, how can it be 1/2 x 26 x 10... coz 26 isnt the breadth or height....its the hypotenuse

Answer 3

oh sorry youre right. so using pythag \[10^{2} + x ^{2} = 26^{2}\]

so 676-100=x^2

sqrt576=24=x

so area of psr = half x 24 x 10 = 120

total = 120 + 156 = 176

Answer 4

yeapz i got it....tq