A circular wire of radius 3 cm is cut and bent so as to lie along the circumference of hoop with radius 48 cm . find in degrees the angle which is subtended at the center of the hoop?

Question

aravindg · Answer

what did u try in this question shameer?

ghazi · Answer

$$\theta= \frac{ arc }{ radius }=\frac{ 3 }{ 48 }=\frac{ 1 }{ 16 }$$ i hope you can do the rest  :) sorry if i am mistaken

ghazi · Answer

convert this in to radians ...or whatever you like :)

anonymous · Answer

Circumfrence = 2 pie * r = 6 pie

theta = L/r

6 pie / 48  =   pie / 8

anonymous · Answer

@ghazi i think..u made a mistake...

anonymous · Answer

@Yahoo!  here theta= arc/ radius , where arc = 2*pi*3=6.24*3=18.72

anonymous · Answer

It is 30 degree right?

anonymous · Answer

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